How do you graph #y=1/2csc(2x)#?

Question

4136 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-24T03:02:01

As below.

#y = (1/2) csc (2x)#

Standard form of cosecant function is #y = A csc(Bx - C) + D#

#A = 1/2, B = 2, C = D = 0#

#Amplitude = |A| = "NONE for cosecant function"#

#"Period " = (2pi) / |B| = (2pi) / 2 = pi#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = 0#

graph{(1/2) csc(2x) [-10, 10, -5, 5]}