# How do you graph y>=1/5x+10 on the coordinate plane?

Aug 22, 2017

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of a inequality to find the boundary line for the inequality.

For $x = 0$

$y = \left(\frac{1}{5} \cdot 0\right) + 10 = 0 + 10 = 10$ or $\left(0 , 10\right)$

For $x = - 10$

$y = \left(\frac{1}{5} \cdot - 10\right) + 10 = - 2 + 10 = 8$ or $\left(- 10 , 8\right)$

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The boundary line will be solid because the inequality operator contains a "or equal to" clause.

graph{(y-1/5x-10)((x+10)^2+(y-8)^2-0.3)(x^2+(y-10)^2-0.3)=0 [-30, 30, -15, 15]}

To complete the chart of the inequality we shade the left side of the line:

graph{(y-1/5x-10)>=0 [-30, 30, -15, 15]}