# How do you graph y=1+sqrt(x-3)?

Dec 16, 2016

Graph is inserted. See the vertex (3, 1) at the $\leftarrow$end

#### Explanation:

graph{1+sqrt(x-3)2 [0, 10, -10, 10]}

The equation ${\left(y - 1\right)}^{2} = x - 1$ representing the parabola of size a = 1/4

and with vertex V(3, 1) is the combined equation to the pair

$y - 1 = \pm \sqrt{x - 3}$

representing two halves of the parabola.

Here,

As $\sqrt{x - 3} \ge 0 , x \ge 3 \mathmr{and} y \ge 1$.

The graph for the other half given by $y = 1 - \sqrt{x - 3}$ follows.

graph{1-sqrt(x-3) [0, 10, -10, 10]}