# How do you graph #y^2/16-x^2/4=1# and identify the foci and asympototes?

##### 1 Answer

Oct 22, 2016

#### Answer:

The foci are

And the asymptotes are

#### Explanation:

The graph is a hyperbola "opens up and down"

The center is

The vertices are

The slopes of the asymptotes are

The equations of the asymptotes are

To determine the foci, we need

The foci are

graph{(y/4)^2-(x/2)^2=1 [-40, 40, -20, 20]}