# How do you graph y>2/3x-1 on the coordinate plane?

Apr 20, 2018

graph{y>2/3x-1 [-10, 10, -5, 5]}

#### Explanation:

First, graph a line with the equation $y = \frac{2}{3} x - 1$. This equation is in the form $y = m x + b$. $\frac{2}{3}$ is the slope and $- 1$ is the y-intercept.
graph{2/3x-1 [-10, 10, -5, 5]}
However, we are graphing an inequality so we're gonna have to shade either the area above the line or below the line. First, let's look at the inequality symbols.

$>$ Greater than
$<$ Less than
$\ge$ Greater than or equal to
$\le$ Less than or equal to

If the inequality includes equal to, then the line will be solid. If not, then the line will be dotted. Since the inequality $y > \frac{2}{3} x - 1$ doesn't contain the equal to, the line will be dotted.

The direction of the inequality sign matters too. If it's greater than, then the top area will be shaded. If it's less than, then the bottom area will be shaded. Since the inequality $y > \frac{2}{3} x - 1$ has greater than, the top area will be shaded.
graph{y>2/3x-1 [-10, 10, -5, 5]}