How do you graph #y=-2cot(2pix)#?

1 Answer
Aug 6, 2018

Answer:

See explanation.

Explanation:

#y = - 2 cot ( 2 pi x ), x ne# asymptotic k/2, k = 0, +-1, +-2, +-3, ...#

The period of both #tan mx and cot mx# is #(pi/m)_(-)#.

Here, the period is #(pi/(2pi))# = #(1/2)_(-)#

See graph, revealing these aspects.
graph{(y sin(2pix)+2cos(2pix))(x-1/2+0.001y)(x+1/2+0.0001y)(x+0.0001y)=0[-1 1 -5/2 3/2]}
For better visual effect,

the graph is not on uniform scale. '1 in x' is '10 in y'.

A note on amplituse

= #(1/4)_(-)#

#= 1/2# (spacing between two consecutive asymptotes).

Seemingly, the amplitude from the equation is 2.

You can see that this is incorrect.