# How do you graph y=-2cot(2pix)?

Aug 6, 2018

See explanation.

#### Explanation:

$y = - 2 \cot \left(2 \pi x\right) , x \ne$ asymptotic k/2, k = 0, +-1, +-2, +-3, ...#

The period of both $\tan m x \mathmr{and} \cot m x$ is ${\left(\frac{\pi}{m}\right)}_{-}$.

Here, the period is $\left(\frac{\pi}{2 \pi}\right)$ = ${\left(\frac{1}{2}\right)}_{-}$

See graph, revealing these aspects.
graph{(y sin(2pix)+2cos(2pix))(x-1/2+0.001y)(x+1/2+0.0001y)(x+0.0001y)=0[-1 1 -5/2 3/2]}
For better visual effect,

the graph is not on uniform scale. '1 in x' is '10 in y'.

A note on amplituse

= ${\left(\frac{1}{4}\right)}_{-}$

$= \frac{1}{2}$ (spacing between two consecutive asymptotes).

Seemingly, the amplitude from the equation is 2.

You can see that this is incorrect.