Question

How do you graph `y=-2cot(2pix)`?

Answer 1

See explanation.

Explanation:

`y = - 2 cot ( 2 pi x ), x ne` asymptotic k/2, k = 0, +-1, +-2, +-3, ...#

The period of both `tan mx and cot mx` is `(pi/m)_(-)`.

Here, the period is `(pi/(2pi))` = `(1/2)_(-)`

See graph, revealing these aspects.
graph{(y sin(2pix)+2cos(2pix))(x-1/2+0.001y)(x+1/2+0.0001y)(x+0.0001y)=0[-1 1 -5/2 3/2]}
For better visual effect,

the graph is not on uniform scale. '1 in x' is '10 in y'.

A note on amplituse

= `(1/4)_(-)`

`= 1/2` (spacing between two consecutive asymptotes).

Seemingly, the amplitude from the equation is 2.

You can see that this is incorrect.