How do you graph #y=-2sec(1/2x)#?

1 Answer
Aug 13, 2018

Answer:

See explanation and graph.

Explanation:

sec values #notin ( - 1, 1 )#

#y = - 2 sec ( 1/2 x ) notin ( -2, 2 ) and x ne# asymptotic (2k+1)pi#,

#k = 0, +-1,+-2, +-3, ...#

The period is the period #(2pi)/(1/2) = 4pi# of #cos ( 1/2 x ).

See graph depicting all these aspects.
graph{(ycos(x/2) +2)(y-2+0x)(y+2+0x)(x+pi+0.0001y)(x-3pi+0.0001y)(x+3pi+0.0001y)(x-pi+0.0001y)=0[-20 20 -10 10]} .