How do you graph #y=-2sec2(x+pi)+3#?

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Answer 1 · 2018-06-16T09:53:07

As below.

#y = - 2 sec (2x + 2pi) + 3#

Standard form of secant function is #y = A sec(Bx - C) + D#

#A = -2, B = 2, C = -2pi, D = 3#

#Amplitude = |A| = "None for secant function"#

#"Period " = (2pi) / |B| = (2pi) / 2 = pi#

#"Phase Shift " = -C/B = (2pi) / 2 = pi, pi " to the right"#

#"Vertical Shift " = D = 3#

graph{-2 sec(2x + 2pi) + 3 [-10, 10, -5, 5]}