How do you graph #y=2sin(2x+pi/2)+3#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

1
Mar 9, 2018

Answer:

Amplitude # = 2#

Period # = pi#

Phase shift # = -(pi/ 4)# #color(white)(aaa)(pi/4)# to the left.

Vertical shift # = 3#

Explanation:

Standard form of equation is #y = a sin(bx + c) + d#

Given = #y = 2 sin (2x + pi/2) + 3#

Amplitude # = a = 2#

Period # = (2pi) / |b| = (2pi) / 2 = pi#

Phase shift # = - c / b = -(pi/2) / 2 = -(pi/ 4)# #color(white)(aaa)(pi/4)# to the left.

Vertical shift # = d = 3#

graph{2sin(2x+(pi/2))+3 [-10, 10, -5, 5]}

Was this helpful? Let the contributor know!
1500
Impact of this question
53 views around the world
You can reuse this answer
Creative Commons License