# How do you graph y=2x-3 using slope and intercept?

Mar 25, 2017

(see below)

#### Explanation:

$y = 2 x - 3$ is in slope-intercept form with
$\textcolor{w h i t e}{\text{XXX}}$slope of $2$ and
$\textcolor{w h i t e}{\text{XXX}}$y-intercept of $- 3$

A y-intercept of $- 3$ means that we have a point on the line at $\left(0 , - 3\right)$

A slope of $2$ means that for every $1$ unit we move in the positive $x$ direction, the corresponding point on the line will go up $2$ in the positive $y$ direction.

Therefore we can deduce the points:
$\textcolor{w h i t e}{\text{XXX}} \left(0 , - 3\right)$
$\textcolor{w h i t e}{\text{XXX}} \left(1 , - 1\right)$
$\textcolor{w h i t e}{\text{XXX}} \left(2 , + 1\right)$
$\textcolor{w h i t e}{\text{XXX}} \left(3 , + 3\right)$
and so on.

Plotting these point and drawing a line through them should give you a graph like: