How do you graph # y = 3/2 cot( pi/2) x #?

1 Answer
Oct 13, 2015

Answer:

it is a strait line graph with a very steep positive gradient.

Did you mean #y = 3/2 cot[ (pi/2)x] = 3/2 cot((pix)/2)# ?

Explanation:

If you did mean that it should be #cot((pix)/2)# then this is a very different question!!!
graph of #y = 3/2 times cot((pix)/2)#
Graph is ABR build using EfofEx

Consider the presented question of #y= 3/2 times cot(pi/2) times x#

#3/2# is a constant

#pi/2# is a constant so #cot(pi/2)# is also a constant

The result is that #x# is multiplied by some constant.

The thing is, are you measuring the angle in degrees or radians?

Note: cot = #1/tan# so in effect you have:

# y = 3/2 times x/(tan(pi/2)) = (3x)/(2 tan(pi/2))#

which may also be written as:

#y = 3/(2 tan(pi/2))" " x#

If just degrees then you would be looking at:

#y ~= 3/(2 times 0.055...) x#

#y ~= 54.7 x# to 1 decimal place.

If on the other hand you are measuring in radians and we have say #(pi " radians")/2# then it is #(180^0)/2 -> tan(90^0)# which is a problem!!!