How do you graph #y=-3sec(pi/2x)#?

1 Answer
Nov 28, 2016

Answer:

The period of the graph is 4. Look for graph #x in [0, 4]#, sans the points oh infinite discontinuity at x = 1 and x = 3, for the part of the graph, for one period.

Explanation:

sec (odd multiple of #pi/2#) = #+-oo#.

The period for the graph is

the period for #cos (pi/2x) = (2pi)/(pi/2) = 4.

#y = +-3#, alternately, when x = an even integer.

#y to +-oo#, as #x to# an odd integer.

graph{ycos(pi/2x)+3=0 [-20, 20, -10, 10]}