Question

How do you graph `y=-3sec(pi/2x)`?

Answer 1

The period of the graph is 4. Look for graph `x in [0, 4]`, sans the points oh infinite discontinuity at x = 1 and x = 3, for the part of the graph, for one period.

Explanation:

sec (odd multiple of `pi/2`) = `+-oo`.

The period for the graph is

the period for #cos (pi/2x) = (2pi)/(pi/2) = 4.

`y = +-3`, alternately, when x = an even integer.

`y to +-oo`, as `x to` an odd integer.

graph{ycos(pi/2x)+3=0 [-20, 20, -10, 10]}