How do you graph y=3tan(2pit) over the interval [-1/2, 1/2]?

Jul 19, 2018

$y = 3 \tan 2 \pi x$.

The period for this graph is $\frac{\pi}{2 \pi} = \frac{1}{2}$

The asymptotes are  2pix = (( 2k + 1 )(pi/2) rArr x = ( 2k + 1 )/4

k = 0, +-1, +-2, +-3, ...#

So, the graph for$x \in \left[- \frac{1}{2} , \frac{1}{2}\right]$ is for

$x \in \left[- \frac{1}{2} , - \frac{1}{4}\right) U \left(- \frac{1}{4} , \frac{1}{4}\right) U \left(\frac{1}{4} , \frac{1}{2}\right]$, excluding infinite

discontinuities at $x = \pm \frac{1}{4}$.

Now see graph.
graph{y-3 tan ( 2 pi x )=0[-0.5 0.5 ]} .