# How do you graph y+4=0?

Oct 18, 2017

See a solution process below:

#### Explanation:

We can solve this for $y$ as:

$y + 4 - \textcolor{red}{4} = 0 - \textcolor{red}{4}$

$y + 0 = - 4$

$y = - 4$

This equation shows for each and every value of $x$ then $y = - 4$.

We can find two points to plot as:

For $x = 0$ then $y = - 4$ or $\left(0 , - 4\right)$

For $x = 5$ then $y = - 4$ or $\left(5 , - 4\right)$

graph{(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

We can now draw a line through the two points giving:

graph{(y+4)(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

We can this is a horizontal line from $- 4$ on the y-axis

Oct 18, 2017

Refer to the explanation.

#### Explanation:

Graph:

$y + 4 = 0$

Solve for $y$ by subtracting $4$ from both sides of the equation.

$y = - 4$

The graph will be a horizontal line at $y = - 4$ because all of the points will be $\left(x , - 4\right)$, where $x = \pm \infty$.