How do you graph #y=4cot(1/3t)# over the interval #[-3pi, 3pi]#?

1 Answer
Mar 28, 2017

Answer:

Using a graphing calculator:
Change the function to #tan#: #y = 4/(tan(1/3t))#

Explanation:

#cot theta = 1/(tan theta)#

Using a graphing calculator:
Change the function to #tan#: #y = 4/(tan(1/3t))#

Make sure your MODE = radians.
Change your WINDOW to Xmin = #-3pi#, Xmax = #3pi#

There are holes at #(-3pi)/2# and #(3pi)/2#

There are vertical asymptotes at #x = 0# and #x = -3pi#

graph{4/tan(x/3) [-10, 10, -5, 5]}