How do you graph #y = 4tan3(x + pi/3) - 6#?

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Answer 1 · 2018-07-11T01:23:13

As Below.

Standard form of tangent function is #y = A tan (Bx - C) + D#

#"Given : " y = 4 tan (3x + pi) - 6#

#A = 4, B = 3, C = -pi, D = -6#

#Amplitude = |A| = "NONE for tangent function"#

#"Period " = pi / |B| = pi/3#

#"Phase Shift " = -C / B = -pi / 3, pi/3 " to the RIGHT"#

#"Vertical Shift " = D = -6#

graph{4 tan(3x + pi) - 6 [-10, 10, -5, 5]}