# How do you graph y>= -4x+3?

Feb 16, 2017

see explanation.

#### Explanation:

Begin by drawing the line with equation $y = - 4 x + 3$

Using $\textcolor{b l u e}{\text{slope and y-intercept}}$

$y = - 4 x + 3 \text{ is in" color(blue)"slope-intercept form}$

$\textcolor{\mathmr{and} a n \ge}{\text{Reminder: }} y = m x + b$

where m represents the slope and b, the y-intercept.

$y = - 4 x + 3 \text{ has "m=-4" and y-intercept } = + 3$

Plot the point (0 ,3) and from this point move 4 down and 1 right, mark the point. (1 ,-1) Repeat to obtain (2 ,-5)

Drawing a straight line through these 3 points gives the graph
$y = - 4 x + 3$

$\text{Since } y \ge - 4 x + 3$ then the region above this line , including the line is required.
graph{y>= -4x+3 [-10, 10, -5, 5]}