# How do you graph y=4x-8?

##### 1 Answer
Nov 29, 2017

Refer to the graph with Slope(m) = 4 and Y-Intercept $= - 8$

#### Explanation:

$y = m x + b$ is the equation of a straight line usually written this way, where $m$ represents the Slope ( or Gradient ) and $b$ the Y-Intercept. It is also in Slope-Intercept Form.

Also,

$m = \frac{r i s e}{r u n}$ or ( Change in y) $/$ (Change in x)

We need to graph $y = 4 x - 8$

We observe that it is already in Slope-Intercept Form.

Hence, Slope = $m = 4$

Y-Intercept $= \left(- 8\right)$

Go to the graph and plot the point the point $\left(0 , - 8\right)$ on the y-axis.

Then rise 4 and run 1. Plot the point $\left(1 , - 4\right)$

Then again "rise 4" and then "run" 1. Plot the point $\left(2 , 0\right)$

Join all these points on the graph and you will find a straight line. graph{4x - 8 [-19.75, 20.25, -14.88, 5.12]}

Also refer to an additional graph available with my suggested solution with points plotted.

Hope this helps.