How do you graph #y=4x-8#?

1 Answer
Nov 29, 2017

Answer:

Refer to the graph with Slope(m) = 4 and Y-Intercept #= -8#

Explanation:

#y = mx + b# is the equation of a straight line usually written this way, where #m# represents the Slope ( or Gradient ) and #b# the Y-Intercept. It is also in Slope-Intercept Form.

Also,

#m = (rise)/(run)# or ( Change in y) #/# (Change in x)

We need to graph #y = 4x - 8#

We observe that it is already in Slope-Intercept Form.

Hence, Slope = #m = 4#

Y-Intercept #= (-8)#

Go to the graph and plot the point the point # (0, -8)# on the y-axis.

Then rise 4 and run 1. Plot the point #(1, -4)#

Then again "rise 4" and then "run" 1. Plot the point #(2, 0)#

Join all these points on the graph and you will find a straight line. graph{4x - 8 [-19.75, 20.25, -14.88, 5.12]}

Also refer to an additional graph available with my suggested solution with points plotted.

Hope this helps.
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