How do you graph $y = - cot (2 x + \frac{π}{2})$ $y=-cot(2x+pi/2)$ ?

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How do you graph $y = - cot (2 x + \frac{π}{2})$ $y=-cot(2x+pi/2)$ ?

1 Answer

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Answer 1 · 2017-03-10T06:05:59

$y = tan (2 x)$ $y= tan(2x)$

Explanation:

$y = - cot (2 x + \frac{π}{2})$ $y= - cot (2x+pi/2)$

Here, the angle i.e. $(2 x + \frac{π}{2})$ $(2x+pi/2)$ lies in second quadrant where, cotangent is negative. Also ,
$cot (\frac{π}{2} + θ) = - tan θ$ $cot (pi/2 + theta)= -tantheta$

So,

$y = tan (2 x)$ $y= tan(2x)$

graph{y=tan(2x) [-1.92, 1.925, -0.961, 0.959]}

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How do you graph $y = - cot (2 x + \frac{π}{2})$ $y=-cot(2x+pi/2)$ ?

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Explanation:

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