How do you graph #y=csc(x/2)-1#?

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Answer 1 · 2018-07-22T17:08:28

See graph and explanation.

#y= csc ( x / 2 ) - 1 notin ( -1 -1, 1 - 1 ) = ( -2, 0 )#

and #x in ( - oo, oo )#,

sans asymptotic and half-period

#x = 2kpi, k = 0, +-1, +-2, +-3,...#

The period = #(2pi)/(1/2) = 4pi#

See illustrative graph.

graph{((y+1)sin(x/2)-1)(y)(y+2)(x)(x^2-(2pi)^2)=0}