# How do you graph #y=secpix#?

##### 1 Answer

Oct 24, 2016

#### Answer:

#### Explanation:

To graph any inverse function like this it is often easier to graph the normal function lightly and then draw the inverse over the top.

so for this graph

which goes through the y-axis at (0,1) has min at (1,-1) and max at (2,1)

with a period of 2. giving you a graph like this,

graph{cos(pix) [-2, 2, -4, 4]}

now let's look at some of the features of the graph and decide what will happen when we do

- any points where y=1 or y=-1 will remain the same
- any points whey y=0 will become an asymptote
- points at
#y= 1/2# will go to# y=2 # , points at#y=2# will go to#y = 1/2# ect.

now we can do a rough sketch of what the graph will look like.

graph{1/(cos(pix)) [-2, 2, -4, 4]}

It is easier to see the relationship if you superimpose them on one another