Question

How do you graph `y=sin^-1x` over the interval `-1<=x<=1`?

Answer 1

Here is the graph of `y=sin^(-1)x`.

Explanation:

Step 1: Sketch the graph of `y=sin x` on `[-pi/2,pi/2]`.

Step 2: Sketch the line `y=x`.

Step 3: Reflect the graph of `y=sin x` about the line `y=x`.