# How do you graph y=sin^-1x over the interval -1<=x<=1?

Here is the graph of $y = {\sin}^{- 1} x$.
Step 1: Sketch the graph of $y = \sin x$ on $\left[- \frac{\pi}{2} , \frac{\pi}{2}\right]$.
Step 2: Sketch the line $y = x$.
Step 3: Reflect the graph of $y = \sin x$ about the line $y = x$.