# How do you graph y=tan(x+(7pi)/6)?

Nov 23, 2016

graph{y-tan(x+3.665)=0 [-10, 10, -5, 5]}

$y = \tan \left(\pi + \left(\frac{\pi}{6} + x\right)\right) = \tan \left(x + \frac{\pi}{6}\right)$

The period of y is $\pi$. !n the graph, the graph for one period

repeats in a cycle.

A convenient choice of one period is $x \in \left(- \frac{2}{3} \pi , \frac{\pi}{3}\right)$. $\pi = 3.14$

in the graph.

As x to pi/3, y to oo$and as x to -2/3pi, y to -oo#. $\left(- \frac{\pi}{6} , 0\right)\$ is in the middle of the graph, where the tangent

crosses the curve. It is called a point of inflexion. Here, y'' = 0.