How do you graph #y=tan(x+(7pi)/6)#?

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Answer 1 · 2016-11-23T09:48:36

graph{y-tan(x+3.665)=0 [-10, 10, -5, 5]}

#y=tan(pi+(pi/6+x))=tan(x+pi/6)#

The period of y is #pi#. !n the graph, the graph for one period

repeats in a cycle.

A convenient choice of one period is #x in (-2/3pi, pi/3)#. #pi=3.14#

in the graph.

As #x to pi/3, y to oo$ and as #x to -2/3pi, y to -oo#.

#(-pi/6, 0)# is in the middle of the graph, where the tangent

crosses the curve. It is called a point of inflexion. Here, y'' = 0.