How do you graph y=x-10?

Jun 10, 2018

graph{y = x-10 [-10, 10, -5, 5]}

Explanation:

The gradient is the coefficient of the x in the equation, so $m = 1$

The c value is the y intercept, which is $c = - 10$

Therefore it's a line going through $\left(0 , - 10\right)$ with a gradient of 1

Jun 10, 2018

Start at (0 -10) make a point go up one and to the right 1 make a second point at ( 1 -9) connect the two points.

Explanation:

The equation is the y intercept form
$y = m x + b$
where
m = the slope think mountain ski slope.
b = the y intercept think beginning.

m in this equation is 1/1
b in this equation is -10

so start at b the y intercept of ( 0, -10)
This is the first point.
Then use the slope y =1 so go up 1
x= 1 so one to the right

$x = 0 + 1 = 1$
$y = - 10 + 1 = - 9$

The second point is then ( 1,-9)

Graph the two points and connect them to form the line.

Jun 10, 2018

$\text{see explanation}$

Explanation:

$\text{one way is to find the intercepts, that is where the graph}$
"crosses the x and y axes"

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"#

$x = 0 \Rightarrow y = 0 - 10 = - 10 \leftarrow \textcolor{red}{\text{y-intercept}}$

$y = 0 \Rightarrow x - 10 = 0 \Rightarrow x = 10 \leftarrow \textcolor{red}{\text{x-intercept}}$

$\text{plot the points "(0,10)" and } \left(10 , 0\right)$

$\text{draw a straight line through them for graph}$
graph{(y-x+10)((x-0)^2+(y+10)^2-0.04)((x-10)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}