# How do you graph y=-x+3/2 using the slope and intercept?

May 16, 2017

graph{y=-x+3/2 [-10, 10, -5.21, 5.21]}
This is the line that you should get from graphing $y = - x + \frac{3}{2}$

#### Explanation:

The format of this equation is $y = m x + b$, where $m$ is the slope and $b$ is the $y$-intercept. Given this, since we know that $b = \frac{3}{2}$, the graph begins at point $\left(0 , \frac{3}{2}\right)$, $\frac{3}{2}$ above the origin $\left(0 , 0\right)$. From here, since the slope is $- 1$, then you can just
begin counting down one, and right one point. From there, you should create a graph similar to the one shown in the answer.

https://weteachscience.org/mentoring/resources/lesson-plans/algebra-1-%E2%80%93-how-to-graph-a-linear-equation-using-slope-and-y

May 16, 2017

See Explanation

#### Explanation:

The function $y = m x + b$ is defined as the equation of a line where $m$ is the slope and $b$ is the $y$-intercept.

In the function you gave

$y = - x + \frac{3}{2}$

The slope is $- 1$ and the $y$-intercept is $\frac{3}{2}$

To graph this, you begin at the point $\left(0 , \frac{3}{2}\right)$ because this is your $y$-intercept. From there, your slope which is $\text{rise"/"run}$ which is $- 1$ means you go down $1$ unit and then right $1$ unit.

Essentially, the graph looks like this: (You can interact with the graph to get the exact points to plot)

graph{-x+3/2 [-10, 10, -5, 5]}