# How do you graph #y=-x+3/2# using the slope and intercept?

##### 2 Answers

graph{y=-x+3/2 [-10, 10, -5.21, 5.21]}

This is the line that you should get from graphing

#### Explanation:

The format of this equation is

begin counting down one, and right one point. From there, you should create a graph similar to the one shown in the answer.

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#### Explanation:

The function

In the function you gave

The slope is

To graph this, you begin at the point

Essentially, the graph looks like this: (You can interact with the graph to get the exact points to plot)

graph{-x+3/2 [-10, 10, -5, 5]}