# How do you integrate int 1/(2x^3)dx?

Nov 2, 2016

$\int \frac{1}{2 {x}^{3}} \mathrm{dx} = \frac{- 1}{4 {x}^{2}} + C$

#### Explanation:

Using the power rule we have:

$\int \frac{1}{2 {x}^{3}} \mathrm{dx} = \int \frac{1}{2} {x}^{-} 3 \mathrm{dx}$

$= \frac{1}{2} \left({x}^{-} \frac{2}{-} 2\right) + C$
$= \frac{- 1}{4 {x}^{2}} + C$