How do you integrate #int 1/x^3dx#?

1 Answer
Nov 5, 2016

Rewrite as #intx^-3dx# and take the anti-derivative.

Explanation:

We first need to recognize that #1/x^3# is equivalent to #x^-3#.

Once we get that far, the problem becomes quite simple to solve.

Do be careful, however, as we are dealing with a negative exponent, so when we add one to the power as we take the anti-derivative, the magnitude of the power will decrease. This also means that our constant will have to be negative as well, since the x term in the integral is positive. Taking the anti-derivative, we get:

#-1/2*x^-2 +C#

This is equivalent to #-1/(2x^2) +C#

As usual, you can check this answer by taking the derivative, which gives you #x^-3#.