How do you integrate #int (x^(3/2)+2x+1)dx#?
1 Answer
Jan 5, 2017
Explanation:
Integrate each term using the
#color(blue)"power rule for integration"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(2/2)|)))#
#rArrint(x^(3/2)+2x+1)dx#
#=1/(5/2)x^(5/2)+2/2x^2+x+c#
#=2/5x^(5/2)+x^2+x+c# where c is the constant of integration.
