How do you integrate int (x^3+2)dx?

2 Answers
Nov 1, 2016

int(x^3+2)dx=x^4/4+2x+c

Explanation:

Using the power rule of integration, intx^ndx=x^(n+1)/(n+1)+c,

int(x^3+2)dx=int(x^3+2x^0)

=x^(3+1)/(3+1)+(2x^1)/1+c

=x^4/4+2x+c

  • Remember to add the constant c, since this is an indefinite integral and constants are removed when the primitive is derived.
Nov 1, 2016

intx^3+2dx

=(x^(3+1))/(3+1)+2x+C

=1/4x^4+2x+C

This is because:

intx^ndx

=(x^(n+1))/(n+1)+C

And also:

intkdx

=kx+C