How do you multiply  (-1+9i)(3-2i)  in trigonometric form?

$\left(- 1 + 9 i\right) \left(3 - 2 i\right) = - 3 + 2 i + 27 i - 18 {i}^{2}$
$- 3 + 29 i + 18$
$15 + 29 i$