How do you multiply  (-2-5i)(-1-6i)  in trigonometric form?

In trigonometric form : $Z = 32.46 \cdot \left(\cos 148.74 + i \sin 148.74\right)$
$\left(- 2 - 5 i\right) \left(- 1 - 6 i\right) = 2 + 17 i + 30 {i}^{2} = 2 - 30 + 17 i = - 28 + 17 i$ since ${i}^{2} = - 1$
Modulas $r = \sqrt{{\left(- 28\right)}^{2} + {17}^{2}} = \sqrt{1073} = 32.46$
Argument $\theta = 180 - {\tan}^{-} 1 \left(\frac{17}{28}\right) = {148.74}^{0}$ As it lies on the 2nd quadrant the angle has been subtracted from ${180}^{0}$ In trigonometric form : $Z = 32.46 \cdot \left(\cos 148.74 + i \sin 148.74\right)$[Ans]