How do you multiply #(3x-2)^2#?

1 Answer
Feb 23, 2017

Answer:

#9x^2-12x+4#

Explanation:

#(3x-2)^2# can be expanded to #(3x-2)(3x-2)#
From here you can use the FOIL method to expand.

The "first" would be #3x*3x=9x^2#
The "outside" would be #3x*-2=-6x#
The "inside," #-2*3x=-6x#
And the "last," #-2*-2=4#

Putting the terms together you get
#9x^2-6x-6x+4#

And combining like terms
#9x^2-12x+4#