How do you multiply #(3x+8y)(x-2y)#?

1 Answer
Jul 2, 2018

Answer:

#3x^2+2xy-16y^2#

Explanation:

#"each term in the second factor is multiplied by each term"#
#" in the first factor"#

#(color(red)(3x+8y))(x-2y)#

#=color(red)(3x)(x-2y)color(red)(+8y)(x-2y)larrcolor(blue)"distribute"#

#=3x^2color(blue)(-6xy)color(blue)(+8xy)-16y^2larrcolor(magenta)"collect like terms"#

#=3x^2+2xy-16y^2#