# How do you multiply 4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)?

Jun 22, 2018

$8 {x}^{2} + 12 {x}^{2} y + 20 x {y}^{2} + 12 {y}^{2}$

#### Explanation:

Since we have no variables outside the parenthesis, we can just multiply the $4$ by every coefficient on the variables. We get

$8 {x}^{2} + 12 {x}^{2} y + 20 x {y}^{2} + 12 {y}^{2}$

Hope this helps!

Jun 22, 2018

$8 {x}^{2} + 12 {x}^{2} y + 20 x {y}^{2} + 12 {y}^{2}$
$4 \left(2 {x}^{2} + 3 {x}^{2} y + 5 x {y}^{2} + 3 {y}^{2}\right)$
Distribute (multiply) the $\textcolor{b l u e}{4}$ to everything inside the parenthesis:
$8 {x}^{2} + 12 {x}^{2} y + 20 x {y}^{2} + 12 {y}^{2}$