How do you multiply #(4x^2 – 9)(8x^2 + 3)#?

1 Answer
Jul 12, 2016

Answer:

The expanded form will be: #32x^4 -60x^2 + 27#.

Explanation:

This problem requires an understanding of the distributive property of multiplication:
#(a + b)c = ac + bc#

Using this rule we can manipulate the polynomial as follows:
#(4x^2 – 9)(8x^2 + 3)#
#= 4x^2(8x^2 + 3) – 9(8x^2 + 3)#
#= 32x^4 + 12x^2 - 72x^2 +27#
#= 32x^4 -60x^2 + 27#