# How do you multiply (4x^2 – 9)(8x^2 + 3)?

Jul 12, 2016

The expanded form will be: $32 {x}^{4} - 60 {x}^{2} + 27$.

#### Explanation:

This problem requires an understanding of the distributive property of multiplication:
$\left(a + b\right) c = a c + b c$

Using this rule we can manipulate the polynomial as follows:
(4x^2 – 9)(8x^2 + 3)
= 4x^2(8x^2 + 3) – 9(8x^2 + 3)
$= 32 {x}^{4} + 12 {x}^{2} - 72 {x}^{2} + 27$
$= 32 {x}^{4} - 60 {x}^{2} + 27$