How do you multiply #(4x+2y+2) (4x+2y-2)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Shwetank Mauria Jun 27, 2018 #(4x+2y+2)(4x+2y-2)=16x^2+16xy+4y^2-4# Explanation: We can write #(4x+2y+2)(4x+2y-2)# as #(z+2)(z-2)#, where #z=4x+2y# and #(4x+2y+2)(4x+2y-2)=(z+2)(z-2)# = #z^2-4# = #(4x+2y)^2-4# = #(4x)^2+2*4x*2y+(2y)^2-4# = #16x^2+16xy+4y^2-4# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1520 views around the world You can reuse this answer Creative Commons License