How do you multiply #(5y-2)(5y+2)#?

2 Answers
Aug 18, 2016

25y^2-4#.

Explanation:

Using the Identity #(a+b)(a-b)=a^2-b^2#.

#:. (5y-2)(5y+2)=(5y)^2-2^2=25y^2-4#.

Aug 18, 2016

#25y^2-4#

Explanation:

We must ensure that each term in the 2nd bracket is multiplied by each term in the 1st bracket. This can be achieved as follows.

#(color(red)(5y-2))(5y+2)=color(red)(5y)(5y+2)color(red)(-2)(5y+2)#

now distribute each pair of brackets and collect 'like terms'

#=25y^2+cancel(10y)-cancel(10y)-4=25y^2-4#