How do you multiply #(8x-11)(8x+11)#?

1 Answer
Feb 19, 2017

Answer:

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(8x) - color(red)(11))(color(blue)(8x) + color(blue)(11))# becomes:

#(color(red)(8x) xx color(blue)(8x)) + (color(red)(8x) xx color(blue)(11)) - (color(red)(11) xx color(blue)(8x)) - (color(red)(11) xx color(blue)(11))#

#64x^2 + 88x - 88x - 121#

We can now combine like terms:

#64x^2 + (88 - 88)x - 121#

#64x^2 + 0x - 121#

#64x^2 - 121#