Question

How do you plot the polar coordinate `(2, (7pi)/6)`?

Answer 1

To plot `(2,(7pi)/6)`, one should plot point `(-sqrt3,-1)` in Cartesian plane.

Explanation:

The relation between polar coordinate `(r,theta)` and Cartesian coordinates `(x,y)` is

`x=rcostheta` and `y=rsintheta`

Hence for `(2,(7pi)/6)` we have `x=2×cos((7pi)/6)=2×(-sqrt3/2)=-sqrt3` and `y=2×sin((7pi)/6)=2×(-1/2)=-1`.

Hence to plot `(2,(7pi)/6)` , one should plot point `(-sqrt3,-1)`.