How do you put $2x-3y=6$ in slope intercept form?

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Answer 1 · 2018-07-26T22:53:38

$y=2/3x-2$

$y=mx+b$ , with slope $m$ and $y$ -intercept of $b$ .

We essentially just want a $y$ on the left side, so let's subtract 2x# from both sides to get

$-3y=-2x+6$

Lastly, let's divide both sides by $-3$ to get

$y=2/3x-2$

Our equation is now in slope-intercept form, where the slope is $2/3$ and our $y$ -intercept is $-2$ .

Hope this helps!

How do you put 2x-3y=62x-3y=6 in slope intercept form?