# How do you rewrite ((a^-2b^5)/c^-3)^-2 using a positive exponent?

Oct 12, 2015

$= \frac{{a}^{4}}{{b}^{10} {c}^{6}}$

#### Explanation:

According to the laws of exponents :

${x}^{- n} = \frac{1}{{x}^{n}}$ and ${\left(x y\right)}^{n} = {x}^{n} {y}^{n}$

Hence, ${\left(\frac{{a}^{- 2} {b}^{5}}{{c}^{- 3}}\right)}^{- 2} = {\left(\frac{{b}^{5} {c}^{3}}{a} ^ 2\right)}^{- 2}$

=(b^(-10)c^(-6))/(a^(-4)

$= \frac{{a}^{4}}{{b}^{10} {c}^{6}}$