How do you simplify #(25-x^2)/(x^2-10x+25)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Nghi N · EZ as pi Aug 4, 2017 #- (x + 5)/(x - 5)# Explanation: #(25 - x^2)/(x^2 - 10x + 25) = ((5 - x)(5 + x))/((x - 5)(x-5))# #=(color(blue)(-cancel((x-5)))(5 + x))/(cancel((x - 5))(x-5))# #= - (x + 5)/(x - 5)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 3003 views around the world You can reuse this answer Creative Commons License
