How do you simplify -3i(2-5i) - (7+i)? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer sudheer22kumar May 11, 2016 -(22 + 7i) Explanation: -3i(2-5i) - (7+i) = -6i + 15i^2 -7 - i = -7i + 15(-1) -7 = -7i - 15 -7 = -7i - 22 or, -(22 + 7i) Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square (1+i)? What is the geometric interpretation of multiplying two complex numbers? What is the product of 3+2i and 1+7i? How do I use DeMoivre's theorem to solve z^3-1=0? How do I find the product of two imaginary numbers? How do you simplify (2+4i)(2-4i)? How do you multiply (-2-8i)(6+7i)? See all questions in Multiplication of Complex Numbers Impact of this question 1695 views around the world You can reuse this answer Creative Commons License