# How do you simplify (4-2i) (3 + 2i)?

Jun 14, 2016

$\left(4 - 2 i\right) \left(3 + 2 i\right) = 16 + 2 i$

#### Explanation:

To simplify $\left(4 - 2 i\right) \left(3 + 2 i\right)$, just multiply them like two binomials, but remember ${i}^{2} = - 1$.

Hence, $\left(4 - 2 i\right) \left(3 + 2 i\right)$

= $4 \left(3 + 2 i\right) - 2 i \left(3 + 2 i\right)$

= $12 + 8 i - 6 i - 4 {i}^{2}$

= $12 + 2 i - 4 \left(- 1\right)$

= $12 + 2 i + 4$

= $16 + 2 i$