How do you simplify #4- sqrt( r+6) = -sqrt( r-2)#?

1 Answer
May 14, 2016

Answer:

#r = 3#

Explanation:

grouping #4= sqrt[r+6]-sqrt[r-2] # and squaring both sides of the equation,
#16 = 4+2r+2sqrt((r+6)(r-2))#
Simplifying and grouping radicals to the right
#6-r=sqrt((r+6)(r-2))#
Squaring again both sides
#(6-r)²=(r+6)(r-2)#
After simplifications we get
#r = 3#