Question

How do you simplify `(4i)(-2i)(-8+4i)`?

Answer 1

`(4i)(-2i)(-8+4i)=-64+32i`

Explanation:

While multiplying complex numbers we should always remember that `i^2=-1`.

Hence, `(4i)(-2i)(-8+4i)`

= `-8i^2×(-8+4i)`

= `-8×(-1)(-8+4i)`

= `8×(-8+4i)`

= `-64+32i`