How do you simplify $(5+4i)(5+4i)$ ?

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Answer 1 · 2016-02-05T16:37:17

9 + 40i

distribute the brackets using FOIL

(5+4i)(5+4i) = $25 +20i+20i+16i^2$

[remember that $i^2 =(sqrt(-1))^2 = -1$ ]

hence $25+20i+20i -16 = 9 + 40i$

How do you simplify (5+4i)(5+4i)(5+4i)(5+4i)?