# How do you simplify (6 + 4i )(3 + 2i )?

Feb 11, 2016

Answer is $10 + 24 i$ and process is detailed below.

#### Explanation:

These are two complex numbers. These are of the form $a + b i$ where $a$ and $b$ are real and $i$ is an imaginary number so that ${i}^{2} = - 1$. Hence in $a + b i$, $a$ is called real part and $b i$ imaginary part,

Now multiplying $\left(6 + 4 i\right) \left(3 + 2 i\right)$ gives us

$18 + 12 i + 12 i + 8 {i}^{2}$ and as ${i}^{2} = - 1$, this becomes

$18 + 12 i + 12 i - 8$ or $10 + 24 i$