# How do you simplify (6i)(-8i)?

Mar 4, 2018

48

#### Explanation:

Considering $i$ as the imaginary number, defined as ${i}^{2} = - 1$

$\left(6 i\right) \cdot \left(- 8 i\right) = \left(- 8 \cdot 6\right) {i}^{2} = - 48 {i}^{2} = 48$

Mar 4, 2018

It becomes 48.

#### Explanation:

If you multiply them together, you get $- 48 {i}^{2}$. Since $i$ is $\sqrt{- 1}$, then ${i}^{2} = - 1$. $- 48 \cdot - 1 = 48$. Hope this helped.