How do you simplify #6sqrt54#?

2 Answers
May 27, 2017

Answer:

#=18sqrt6#

Explanation:

the first step when working with roots is to find the factors of the radicand. (#54#), using squares if possible.

#6sqrt54 = 6 sqrt(9xx6)" "larr# find the roots if possible.

#6 sqrt(9xx6)" "larr (sqrt9 =3)#

#=6 xx 3sqrt6#

#=18sqrt6#

May 27, 2017

Answer:

#color(brown)(18sqrt6#

Explanation:

#6sqrt54#

#:.=6sqrt(3*3*3*2)#

#:.sqrt3 xx sqrt3=3#

#:.=6sqrt(underline(3*3)*3*2)#

#:.=6 xx 3sqrt6#

#:.color(brown)(=18sqrt6#